Momentum ballistics speed question

AI Thread Summary
The discussion revolves around calculating the time a bullet spends in a target during a ballistic test. A user attempts to use the average velocity formula but arrives at an incorrect result. The bullet's initial speed is 1100 m/s, and it exits the target at 900 m/s after penetrating a 30 cm thick target. There is confusion regarding the correct application of kinematic equations to determine the bullet's retardation and time in the target. Clarification is sought on the proper method to solve these ballistic calculations.
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In a ballistics test, a 25.0 g bullet traveling horizontally at 1100 m/s goes through a 30.0 cm-thick 450 kg stationary target and emerges with a speed of 900 m/s. The target is free to slide on a smooth horizontal surface.

How long is the bullet in the target?
i tried to use this equation : t = d/v_avg

900-1100 / 2 = -100 = vavg
.3=-100 t
t= .003
but it is saying that it is incorrect. can someone tell me what i am doing wrong?
 
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um i guess not then...
 
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