Momentum homework but a velocity question

[iuhoosierz]

This is momentum homework but a velocity question. I can't even figure out where to start with this one. The question is "For your answer for question E (which was V=233m/s) 70% of that velocity goes upward and 70% goes horizontally (45 degree angle). How far will the baseball go (ignoring air resistance)?

I am not given time so not really sure how to do this one. I was going to try the distance equations of D=1/2A*t^2 and D=avg V*T but I don't have enough info to use those.

Can anyone tell me where to start?
Thanks

 

[Doc Al]

You can figure out the time. You know the initial velocity in the vertical direction, so how long does it take to reach max height? To fall back down to the ground?

 

[iuhoosierz]

So the initial velocity in the vertical direction is 163m/s. Do I need to factor in gravity? So would I take 163m/s / 10m/s? So the time to reach it's max height would be 16.3 seconds? I don't think that sound right

 

[Doc Al]

Of course you must factor in gravity! But you're doing fine, using v=gt. Sounds good to me. Keep going.

 

[iuhoosierz]

So since the volocity of 163m/s is the same in the horizontal direction would I do the same thing? V=gt?

 

[Doc Al]

No. Gravity only affects the vertical motion. What's the total time the baseball is in the air? How fast does it move horizontally? How far does it get?

 

[iuhoosierz]

total time would be 32.6s? It's going 163m/s horizontally so would it be D=avg v*t?

 

[Doc Al]

Sounds good to me.

 

[iuhoosierz]

So the total distance is 5313.8m? That seems really far

 

[Doc Al]

It's moving pretty fast. And we're neglecting air resistance.

 

[iuhoosierz]

ok thanks for all your help!