Momentum of System Homework: Total Momentum at h/2

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The discussion centers on calculating the total momentum of a system consisting of a ball and the Earth when the ball has fallen a distance of h/2. The initial attempts at solutions suggest options B and C, with confusion regarding the correct answer. The momentum of the ball is calculated using the formula p = m√(2ad), while the Earth's momentum must also be considered. The total momentum is the sum of the ball's and Earth's momenta, but a clear answer is not provided in the thread. Further clarification and intuitive approaches are sought by participants.
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Homework Statement


A system initially consists of a ball of mass m at rest at a height h above the Earth and the Earth, of mass Me. When the ball has fallen a distance h/2, the total momentum of
the system is
A. 0
B. m(sqrrt)2gh
C. Me(sqrrt)2gh
D. Me + m(sqrrt)2gh
E. Me - m(sqrrt)2gh


Homework Equations





The Attempt at a Solution


I put B and missed it. I think the answer is C but not sure.
Any help understanding this would be appreciated.
Thanks,
Kevin
 
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Husker70 said:

Homework Statement


A system initially consists of a ball of mass m at rest at a height h above the Earth and the Earth, of mass Me. When the ball has fallen a distance h/2, the total momentum of
the system is
A. 0
B. m(sqrrt)2gh
C. Me(sqrrt)2gh
D. Me + m(sqrrt)2gh
E. Me - m(sqrrt)2gh


Homework Equations





The Attempt at a Solution


I put B and missed it. I think the answer is C but not sure.
Any help understanding this would be appreciated.
Thanks,
Kevin


\textbf{v}_f^2=\textbf{v}_i^2+2\textbf{ad}

so, \textbf{v}=\sqrt{2\textbf{ad}}, and:

\textbf{p}=m\textbf{v}=m\sqrt{2\textbf{ad}}.

The total momentum of the system is the sum of momenta of the particles. The above momentum is that of the ball. The momentum of the Earth is given by:

M_e\textbf{v_e}=,

add them and that's your answer which isn't readily available, sadly. Maybe someone else has more of an intuitive approach.
 
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