- #1

Nightrider55

- 18

- 0

## Homework Statement

Force F_x =(10N){sin({(2pi(t))/4.0s) (where t in (m/s) is exerted on a 420 g particle during the interval 0 less than or equal to T is less than or equal to 2 seconds.

If the particle starts at rest what is its speed at t=2 seconds?

## Homework Equations

Jx= area under the Fx(t) cureve between Ti and Tf

Pfi-Pix=Jx

## The Attempt at a Solution

This problem looks fairly easy but I am having trouble setting it up. I took the integral of the force over the time interval and got .54817 Ns which should be the impulse. I then used this to find Pfx by the equation above. I then used Vfx=(Pfx/m) to find the final velocity which came out to be 2.19 m/s but its wrong, any insight as to what I did wrong?