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can someone please help me with this problem?

A 10kg cart with low friction wheels has a 4000N/m

spring on one end. The cart is pressed against the

wall so that the spring is compressed 0.50m. The cart

is released and rolls on the surface only to hit

another identical cart. The two carts lock together

and run into a wall on the other side of the room

where a 4000N/m spring on the second cart compresses

until the carts stop. How far does the second spring

compress as the carts stop?

I think i need to break it up into three parts. For

the first one i need to find the force of the s[ring

then the collision of hte two carts and then the

compression of the spring. So for the first part i

did:

PEs = (1/2) k(x^2) = (1/2)(4000N/m)(0.50^2) = 1000J

is that right for the first part?

A 10kg cart with low friction wheels has a 4000N/m

spring on one end. The cart is pressed against the

wall so that the spring is compressed 0.50m. The cart

is released and rolls on the surface only to hit

another identical cart. The two carts lock together

and run into a wall on the other side of the room

where a 4000N/m spring on the second cart compresses

until the carts stop. How far does the second spring

compress as the carts stop?

I think i need to break it up into three parts. For

the first one i need to find the force of the s[ring

then the collision of hte two carts and then the

compression of the spring. So for the first part i

did:

PEs = (1/2) k(x^2) = (1/2)(4000N/m)(0.50^2) = 1000J

is that right for the first part?

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