Calculating Average Force: Momentum Question

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To calculate the average force between a baseball and bat, the change in momentum must be determined using the change in velocity, which is 91 m/s. The initial calculation of 1.89 kg*m/s was incorrect because it did not account for the direction change of the ball. The correct average force, factoring in the change in velocity and the contact time of 0.001 seconds, is 13,200 N. The importance of considering direction in momentum calculations is emphasized. Accurate calculations require attention to both magnitude and direction of velocity changes.
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This seems like an easy question.
A 0.145 kg baseball pitched at 39.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between the bat and ball is 0.001 seconds, calculate the average force between the ball and bat during contact.

I used Average Force= change in momentum divided by change in time.
I figured the change in momentum to be 1.89 kg*m/s and change in time to be .001 seconds. Dividing, I got 1,890 N. The answer given by the textbook is 13,200 N.
 
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HINT: The change in velocity is 91 m/s.
 
you need to use the change in velocity. make sure to take the directions into account.

edit:

tide beat me to it! =p
 
Gotta be quick, Andrew! ;)
 
That's right, i forgot velocity was changing directions. Thank you.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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