'Monk and the Monastery' problem

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Homework Help Overview

The problem involves a scenario where a monk travels between a city and a monastery, and participants are exploring whether there is a point along the path that he passes at the same time each day. The discussion revolves around the monk's position and time as he makes this journey.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to establish equations for the monk's position in relation to time. There are discussions about the implications of constant velocity and how to express this mathematically. Some participants question how to explain their reasoning without relying on visual aids like graphs.

Discussion Status

The discussion is active, with participants sharing equations and attempting to clarify their understanding of the variables involved. There is a mix of interpretations regarding the equations and the relationships between distance, time, and velocity. Some guidance has been offered, but no consensus has been reached on the correct approach.

Contextual Notes

Participants are working under the constraints of the problem statement, which specifies certain values and relationships. There is some confusion regarding the definitions of variables and how to apply them correctly in the context of the equations being discussed.

Kingyou123
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Homework Statement


Check attached image. Is there any point along the path that he passes at the same time each day

Homework Equations


None that I know of...

The Attempt at a Solution


The whiteboard image, I'm not sure if that's how the graph is suppose to look like.
 

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I do believe that there is a point where the monk would be at the same position at the same time at on both days, but how would I explain it without" saying look at my graph"?
 
Kingyou123 said:
I do believe that there is a point where the monk would be at the same position at the same time at on both days, but how would I explain it without" saying look at my graph"?
Let's try to write down some equations. Suppose that you mark off time as hours since noon and you mark off position as current distance from the city. Can you write down an equation for the man's position in terms of time during the trip from city to monastery?
 
xf=x0+v0(t) t=hours and x= position
 
Kingyou123 said:
xf=x0+v0(t) t=hours and x= position
Can you write down v0 in terms of D?
 
If the velocity constant then the [v][/0] would be D/t
 
Kingyou123 said:
If the velocity constant then the [v][/0] would be D/t
You may want to rethink that. In the equation you gave, t is a variable. But velocity is a constant.
 
xf=xo+x(t)?
 
Kingyou123 said:
xf=xo+x(t)?
Hint: You know how long it takes to get from the city to the monastery.
 
  • #10
jbriggs444 said:
Hint: You know how long it takes to get from the city to the monastery.
xf=xo+x(7), 7 is the number of hours from the office to the monastery.
 
Last edited:
  • #11
Kingyou123 said:
xf=xo+x(7), 7 is the number of hours from the office to the monastery.
The problem statement specifies the value for xf.
 
  • #12
jbriggs444 said:
The problem statement specifies the value for xf.
D=0+v(7) would the second equation be D=D+v(3)?
 
  • #13
Kingyou123 said:
D=0+v(7) would the second equation be D=D+v(3)?
The thing that confuses me is what to solve for, D?
 
  • #14
Refer to post #5.
 
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  • #15
jbriggs444 said:
Refer to post #5.
V0=(xf-x0)/t
 
  • #16
Kingyou123 said:
V0=(xf-x0)/t
What is x0? What is xf? And, for that matter, what is t?
 
  • #17
jbriggs444 said:
What is x0? What is xf? And, for that matter, what is t?
t= times from office to monastery or time from monastery to office
xf=is the distance between the monastery and office
x0=is zero since its the starting distance
 
  • #18
Kingyou123 said:
t= times from office to monastery or time from monastery to office
Given that t=7 and xf-x0 = D, can you simplify the formula for the velocity on the trip from office to monastery?
 
  • #19
I already figure out that step the two formulas set equal to each other would be (D/7)(t)=D-(D/3)t. My answer is 2.1 hours, I'm just having trouble finding the formula to plug it in. Sorry for being confused, in post #6 I had v0= D/t and I thought you meant it was wrong so I completely threw out that answer.
 

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