Let's try to write down some equations. Suppose that you mark off time as hours since noon and you mark off position as current distance from the city. Can you write down an equation for the man's position in terms of time during the trip from city to monastery?Kingyou123 said:
Can you write down v0 in terms of D?Kingyou123 said:
You may want to rethink that. In the equation you gave, t is a variable. But velocity is a constant.Kingyou123 said:
Hint: You know how long it takes to get from the city to the monastery.Kingyou123 said:
xf=xo+x(7), 7 is the number of hours from the office to the monastery.jbriggs444 said:
The problem statement specifies the value for xf.Kingyou123 said:
D=0+v(7) would the second equation be D=D+v(3)?jbriggs444 said:
The thing that confuses me is what to solve for, D?Kingyou123 said:
V0=(xf-x0)/tjbriggs444 said:
What is x0? What is xf? And, for that matter, what is t?Kingyou123 said:
t= times from office to monastery or time from monastery to officejbriggs444 said:
Given that t=7 and xf-x0 = D, can you simplify the formula for the velocity on the trip from office to monastery?Kingyou123 said:
The 'Monk and the Monastery' problem is a math puzzle that involves a monk walking around a circular path in a monastery. The monk starts walking from a particular point on the path and counts each time he passes the starting point. The problem asks for the total number of times the monk will have to walk around the path in order to reach a certain number of counts.
The 'Monk and the Monastery' problem is believed to have originated in ancient China. It was used as a meditation exercise for monks to practice counting while walking. It has also been referenced in various works of literature, including a story by Jorge Luis Borges.
The 'Monk and the Monastery' problem can be solved using a mathematical formula. The formula is (n/m) - 1, where n is the desired number of counts and m is the number of counts the monk makes each time he passes the starting point. For example, if the monk makes 3 counts each time he passes the starting point and wants to reach 10 counts, the formula would be (10/3) - 1 = 2, meaning the monk would have to walk around the path 2 times.
Yes, there are several variations of the 'Monk and the Monastery' problem. Some variations involve different starting and ending points, while others involve multiple monks walking at different speeds. These variations may require different formulas or approaches to solve.
The 'Monk and the Monastery' problem may seem like a simple math puzzle, but it has been used to teach various mathematical concepts, such as divisibility and modular arithmetic. It also highlights the importance of understanding and using mathematical formulas in problem-solving. Additionally, some people use this problem as a brain teaser or a meditation exercise.
