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'Monk and the Monastery' problem

  1. Sep 7, 2015 #1
    1. The problem statement, all variables and given/known data
    Check attached image. Is there any point along the path that he passes at the same time each day

    2. Relevant equations
    None that I know of...

    3. The attempt at a solution
    The whiteboard image, I'm not sure if that's how the graph is suppose to look like.
     

    Attached Files:

  2. jcsd
  3. Sep 7, 2015 #2
    I do believe that there is a point where the monk would be at the same position at the same time at on both days, but how would I explain it without" saying look at my graph"?
     
  4. Sep 7, 2015 #3

    jbriggs444

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    Let's try to write down some equations. Suppose that you mark off time as hours since noon and you mark off position as current distance from the city. Can you write down an equation for the man's position in terms of time during the trip from city to monastery?
     
  5. Sep 7, 2015 #4
    xf=x0+v0(t) t=hours and x= position
     
  6. Sep 7, 2015 #5

    jbriggs444

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    Can you write down v0 in terms of D?
     
  7. Sep 7, 2015 #6
    If the velocity constant then the [v][/0] would be D/t
     
  8. Sep 7, 2015 #7

    jbriggs444

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    You may want to rethink that. In the equation you gave, t is a variable. But velocity is a constant.
     
  9. Sep 7, 2015 #8
    xf=xo+x(t)?
     
  10. Sep 7, 2015 #9

    jbriggs444

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    Hint: You know how long it takes to get from the city to the monastery.
     
  11. Sep 7, 2015 #10
    xf=xo+x(7), 7 is the number of hours from the office to the monastery.
     
    Last edited: Sep 7, 2015
  12. Sep 7, 2015 #11

    jbriggs444

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    The problem statement specifies the value for xf.
     
  13. Sep 7, 2015 #12
    D=0+v(7) would the second equation be D=D+v(3)?
     
  14. Sep 7, 2015 #13
    The thing that confuses me is what to solve for, D?
     
  15. Sep 7, 2015 #14

    jbriggs444

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    Refer to post #5.
     
  16. Sep 7, 2015 #15
    V0=(xf-x0)/t
     
  17. Sep 7, 2015 #16

    jbriggs444

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    What is x0? What is xf? And, for that matter, what is t?
     
  18. Sep 7, 2015 #17
    t= times from office to monastery or time from monastery to office
    xf=is the distance between the monastery and office
    x0=is zero since its the starting distance
     
  19. Sep 7, 2015 #18

    jbriggs444

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    Given that t=7 and xf-x0 = D, can you simplify the formula for the velocity on the trip from office to monastery?
     
  20. Sep 7, 2015 #19
    I already figure out that step the two formulas set equal to each other would be (D/7)(t)=D-(D/3)t. My answer is 2.1 hours, I'm just having trouble finding the formula to plug it in. Sorry for being confused, in post #6 I had v0= D/t and I thought you meant it was wrong so I completely threw out that answer.
     
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