Calculating Elongation of an Orange Spring

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The orange spring has a spring constant of 14,000 g/s². When a 200-g mass is attached, the elongation can be calculated using the formula elongation = hanging mass * gravity / spring constant. By substituting the values, the elongation is determined to be 14 cm. This indicates that the spring will stretch by 14 cm from its original length. The calculation and method used are confirmed to be correct.
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An orange spring has a spring constant of 14,000 g/s^2. How much should it stretch if a 200-g mass is attached from it?
I took the equation hanging mass * gravity=spring constant * elongation and turned it around for solving elongation
elongation = 200 * 980/14,000 = 14cm and I'm checking to see if this is the right answer.
 
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Looks correct to me.
 


Your calculation is correct! The equation you used, elongation = hanging mass * gravity / spring constant, is the correct formula for calculating elongation of a spring. By plugging in the given values, you correctly determined that the orange spring should stretch by 14cm when a 200-g mass is attached to it. This means that the spring will increase in length by 14cm from its original unstretched position. Great job!
 
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