Ammar w
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Homework Statement
An object moves along the x-axis according to the equation x = 3.00t2 - 2.00t + 3.00 , where x is in meters and t is in seconds.
Determine :
(a) the average speed between t = 2.00 s and t = 3.00 s.
(b) the instantaneous speed at t = 2.00
(c) the average acceleration between t = 2.00 s and t = 3.00 s.
(d) the instantaneous acceleration at t = 2.00 s
(e) at what time is the object at rest?
Homework Equations
average speed = \frac{d(total distance travelled)}{\Delta t}
instantaneous speed = \frac{dx}{dt}
\overline{a} (average acceleration) = \frac{\Delta v}{\Delta t}
a (instantaneous acceleration) = \frac{dv}{dt} = \frac{dx^2}{dt}
The Attempt at a Solution
(a) I couldn't calculate the total distance.
(b) instantaneous speed = instantaneous velocity = \frac{dx}{dt} = 6.00t - 2.00
instantaneous speed at t=2.00 = 6.00(2)-2.00 = 10 m/s
(c) \overline{a} = \frac{\Delta v}{\Delta t} = \frac{vf-vi}{1} = \frac{v(3)-v(2)}{1} = \frac{16-10}{1} = 6 m/s2
(d) a = \frac{dx^2}{dt} = 6 => a at 2.00s = 6 m/s2
(e) the rest means that v = 0
=> 6t-2=0
=>t=0.33 s //it seems wrong.