Moving about, velocity, speed, of objects

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A train is moving at a constant speed of 20 m/s when its last carriage is released, which then comes to a rest after traveling 200 meters. The acceleration of the carriage was calculated using the equation v^2 = u^2 + 2ar, and the time taken to stop was found using v = u + at. To determine how far ahead the train was when the carriage stopped, the distance traveled by the train during the time it took the carriage to stop was calculated. The final result showed that the train was 200 meters ahead of the carriage when it came to rest. The discussion highlights the application of kinematic equations to solve motion problems.
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i have this killllerrr question i need some help on. idno what to do..

Homework Statement


A train is moving at a constant speed of 20ms per second along a striahgt, level track when its last carriage is released. This carriage comes to a rest after continuing for 200m along the track. the speed of the train remains constant.

a.) what was the acceleration of the carriage.
b.) how long did it take for the carriage to come to a rest?
c.) how far ahead of the carriage was the train when the carriage stoped?


Homework Equations


i got the first 2, using v^2 = u^2 + 2ar, and v = u + at

idno how to get the last answer.


The Attempt at a Solution


no idea.
 
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Find the distance traveled by the carriage after it got disengaged from the train. Also find the distance traveled by the train during the same period of time. See what to do next?
 
how do i know when it got disengaged?
cos it just says the carriage got disengaged from a train goin 20msper second :S
 
no wait!
hahah i got it man

thanks bud
what i did was
r = ut + 1/2at^2

because i got the time from part B

turned out to be 200metres ahead :D


thanks man
 

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