Moving down on a frictionless plane

AI Thread Summary
A shipping container is being hauled up a frictionless ramp at a constant speed of 2.10 m/s using a force of 2250 N on a 24.7° incline. The relevant equations include the force of gravity and the applied force, leading to the conclusion that the applied force equals the x component of gravity. The calculations attempted suggest a mass of approximately 23.45 kg, but this answer was deemed incorrect. The discussion highlights confusion over the correct application of the formulas and the lack of feedback from the problem source. The participants are seeking clarification on the correct approach to solve for the container's mass.
lacar213
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Homework Statement


A shipping container is hauled up a roller ramp that is effectively frictionless at a constant speed of 2.10 m/s by a 2250 N force that is parallel to the ramp. If the ramp is at a 24.7° incline, what is the container's mass?


Homework Equations


Fx = mg sin(theta)
F = ma
A = Fx / m


The Attempt at a Solution


I tried the equations above but I'm unsure if I'm doing this correctly ...
2250/9.8 = 229.592
229.592sin(24.7)=95.9389
2250/95.9389=23.4524 kg
 
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Yes I think you are doing it correctly.

Since it is at a constant speed that means no acceleration hence no Fnet (N2)

So the force that is pushing it up should be equal the the x component of gravity.

Fgx=Fapplied

mgsin(theta)=Fapplied
 
these problems are on the Kinematic Books website - that answer ended up being incorrect - it doesn't tell you what the correct answer is

I'm not sure what I did wrong ... I tried that problem 3 times
 
these problems are on the Kinematic Books website - that answer ended up being incorrect - it doesn't tell you what the correct answer is

I'm not sure what I did wrong ... I tried that problem 3 times
 

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