Moving electrons and magnetic fields

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An electron moving through a 0.002T magnetic field experiences a force calculated using the Lorentz force equation, F = QVB, where Q is the charge of the electron, V is its velocity, and B is the magnetic field strength. Given the electron's velocity of 3x10^5 m/s and the magnetic field being perpendicular to its motion, the angle is 90 degrees, resulting in sin(90) = 1. This simplifies the force calculation to F = Q * V * B. The discussion emphasizes the importance of using the Lorentz force for accurate calculations in magnetic fields. Understanding these principles is crucial for applications in electromagnetism.
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An electron is moving through a 0.002T magnetic field as described below. Show the direction the electron will be pushed by the magnetic field, and calculate teh amount of force exerted on the electron if the electron is moving at 3x10^5 m/s


here is what the paper looks like

x x x x x x x x

x x x x x x x x

x x x x x x x x

x x x x x x x x
^
e - is going straight thru the middle of the x's

I'm assuming B=.002T and the equation I would use is Fbw = BIL?
 
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Do a search on "Lorentz Force".
 
NO NEED AT ALL TO USE THAT BIL?IS THERE ANY CURRENT HERE?
gneill is right!
USE LORENTZ FORCE WHICH FOR MAGNETIC FIELD IS:F=QVB.
HERE Q IS CHARGE, VELOCITY OF CHARGE AND B IS MAGNETIC FIELD APPLIED.
ACTUALLY IT IS VROSS-PRODUCT OF V & B VECTOR.(V x B=VB*sin(m) WHERE M IS ANGLE WHICH FIELD MAKES WITH PLANE IN WHICH CHARGE IS LOCATED)
IN YOUR QUESTION THE X X X
X X X MEANS THAT MAGNETIC FIELD IS PERPENDICULAR TO CHARGE.
=>M=900 OR 90 DEGREES.NOW SIN(90)=1.
THEREFORE F=QVB!
REMEMBER LORENTZ FORCE IS OBTAINED FROM EXPERIMENT'S--WE ARE THUS FORCED TO REMEMBER IT WITHOUT PROOF!
 
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