Multiplication of matrices properties

bonfire09
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Homework Statement


Let ej denote the jth unit column that contains a 1 in the jth
position and zeros everywhere else. For a general matrix An×n, describe the following products. (a) Aej (c) eTiAej?

Homework Equations


Rows and Columns of a Product
Suppose that A = [aij] is m × p and B = [bij] is p × n.
• [AB]i∗ = Ai∗B [( ith row of AB)=( ith row of A) ×B]. (3.5.4)

• [AB]∗j = AB∗j [ (jth col of AB)=A× ( jth col of B)]. (3.5.5)

• [AB]i∗ = ai1B1∗ + ai2B2∗ + · · · +aipBp∗aikBk∗. (3.5.6)

• [AB]∗j = A∗1b1j + A∗2b2j + · · · + A∗pbpjA∗kbkj (3.5.7)

These last two equations show that rows of AB are combinations of
rows of B, while columns of AB are combinations of columns of A.

The Attempt at a Solution


For parts a and c I am not even sure what they are even asking for. When its saying ej is a unit column does that mean like this (1 0 0...0) as an example? For part A wouldn't the solution of Aej just just be a linear combination a column of A and the entries of ej as scalars?
 
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Yes, it means that ej = (δij)T, i.e. 1 where i=j and zero elsewhere.
From your matrix multiplication formulae, can you deduce a formula for B being a column vector instead of a matrix?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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