Multiplying a determinant by a constant? book says

mr_coffee
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I'm confused, this question had 5 parts and i got the other 4 but this one I keep missing...
If A is a 2x2 matrix...
Det(A) = -5;
The Det(-3A);
The book said, if u multiply a column by a constant k then the determinant is also multiplied by k. So wouldn't the answer just be (-5)(-3) = 15?
Det(-3A) = 15? it says its wrong htough...:bugeye:
 
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Evaluate \left|\begin{array}{cc} ka& kb \\ kc&kd\end{array}\right|... and compare it to \left|\begin{array}{cc} a& b \\ c&d\end{array}\right|. Next try the 3x3 case.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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