Musical Tube and String (Standing wave)

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SUMMARY

The discussion focuses on calculating the fundamental frequency of oscillation for a brass tube closed at one end and a wire stretched near its open end. The brass tube has a mass of 20 kg and a length of 1.1 m, while the wire has a mass of 9.6 g and a length of 0.4 m. The fundamental frequency of the air column in the tube can be determined using the formula f = v/(4L), where v is the speed of sound in air and L is the length of the tube. Additionally, the tension in the wire can be calculated using the equation Tension = (u/(time*L)), where u represents the mass per unit length of the wire.

PREREQUISITES
  • Understanding of fundamental frequency in acoustics
  • Knowledge of wave equations and resonance
  • Familiarity with tension calculations in strings
  • Basic principles of sound propagation in tubes
NEXT STEPS
  • Calculate the speed of sound in air to determine the frequency of the air column
  • Learn about the relationship between tension and frequency in vibrating strings
  • Explore the concept of resonance in closed-end tubes
  • Investigate the effects of mass and length on the fundamental frequency of strings
USEFUL FOR

Students studying physics, particularly those focusing on acoustics and wave mechanics, as well as educators seeking to explain the principles of resonance and oscillation in musical instruments.

turandorf
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Homework Statement


A brass tube of mass 20 kg and length 1.1 m is closed at one end. A wire of mass 9.6 g and length 0.4 meters is stretched near the open end of the tube. When the wire is plucked, it oscillates at its fundamental frequency. By resonance, it sets the air column in the tube oscillating at the column's fundamental frequency.

a) What is the frequency of oscillation of the air in the tube ?

b) What is the tension in the wire?

Homework Equations


Tension=(u/(time*L)) where u is the mass/length and L is the total length


The Attempt at a Solution


I know we need natural freq. but I don't know how to find it from the given data. I think the wave length is 1.1m or some fraction of that length. Any help would be appreciated.

 
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The fundamental frequency can be surmised from the length of the tube can't it?

f = v/(4L)

Since it is the same fundamental frequency of the wire, and you know the mass/unit length of the wire, ...
 

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