Mutual Inductance: Coil 1 Excited, Coil 2 Open Circuited

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Discussion Overview

The discussion revolves around the concept of mutual inductance in a scenario where one coil is excited while the other is left open-circuited. Participants explore the nature of magnetic flux linking the coils and the implications of removing one coil from the system.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions why there is mutual flux (Φ21) linking coil 1 when coil 2 is open-circuited, suggesting that they expected Φ21 to be zero.
  • Another participant clarifies that the mutual flux (Φ21) is independent of the second coil's circuit condition and will not be zero due to its nature of interlinking with both windings.
  • A different participant inquires about the behavior of flux in the magnetic core if the second coil is removed, asking whether only leakage flux would remain.
  • One participant asserts that when the second coil is open-circuited, the first coil behaves as if it is the only inductor present, indicating that the flux (Φ21) remains unchanged even if the second coil is removed.
  • A later reply raises a question about the appropriate number of turns to use in a magnetic field equation when one coil is not connected, seeking clarification on whether to use the total number of turns or just the driven coil's turns.

Areas of Agreement / Disagreement

Participants express differing views on the implications of having one coil open-circuited, particularly regarding the nature of mutual flux and the behavior of the magnetic core. The discussion remains unresolved as participants explore these concepts without reaching a consensus.

Contextual Notes

There are assumptions regarding the definitions of leakage flux and mutual flux that are not fully explored. The discussion also involves unresolved questions about the effects of coil configurations on magnetic behavior.

ezcheez
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I have a very basic question regarding mutual inductance.

Consider a basic square loop with two coils wound on opposite sides from each other, with coil one excited while coil two si left open circuited. The total flux linking coil 1 is

Φ11 = Φl121

where

Φ11 is the total flux linking coil 1
Φl1 is the leakage flux and
Φ21 is the mutual flux linking both coils

My question is why there is mutual flux if the second coil is open-circuited, in other words, why is Φ21 non-zero? I would expect flux through the iron core due to coil one but how/why does coil two contribute to this flux?
 
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Here \phi_{l1} is the leakage flux i.e., the flux which is linking only with first winding and not with second winding and is due to imperfect coupling. The flux \phi_{l21} is the one which interlinks with both windings. Since \phi_{l21} has nothing to do with the second coil's open or short circuit conditions it won't be zero. You may refer the Wikipedia's page below
http://en.wikipedia.org/wiki/Leakage_inductance
 
Let me take step back and ask this question:

What would happen to the flux in the magnetic core if the second coil is removed? Does only the leakage flux remain, or would some flux still flow through the whole core?
 
In fact when the second coil is open circuited, the first coil behaves as if it is the only inductor present in the core. So even if the second coil is removed, the flux going through the core \phi_{l21} will be the same.
 
That helps a great deal. I am going to ponder that for a little while...
 
n.karthick said:
In fact when the second coil is open circuited, the first coil behaves as if it is the only inductor present in the core. So even if the second coil is removed, the flux going through the core \phi_{l21} will be the same.
Hey Karthick,
This is different you have been discussing,Should I use N1+N2 for the no.of turns in the B=U0NI/L where both the coils are one over the other , but one is NOT Connected?
Or should I take only N1 or N2 which ever coil is driven by DRIVE CIRCUIT.

Regards
Geetika
 

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