I have a very basic question regarding mutual inductance.(adsbygoogle = window.adsbygoogle || []).push({});

Consider a basic square loop with two coils wound on opposite sides from each other, with coil one excited while coil two si left open circuited. The total flux linking coil 1 is

Φ_{11}= Φ_{l1}+Φ_{21}

where

Φ_{11}is the total flux linking coil 1

Φ_{l1}is the leakage flux and

Φ_{21}is the mutual flux linking both coils

My question is why there is mutual flux if the second coil is open-circuited, in other words, why is Φ_{21}non-zero? I would expect flux through the iron core due to coil one but how/why does coil two contribute to this flux?

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# Mutual Inductance: Coil 1 Excited, Coil 2 Open Circuited

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