My Physics homework regarding energy/velocity?

AI Thread Summary
The discussion focuses on a physics homework problem involving a ball's energy and velocity during a fall and rebound. The initial potential energy is calculated as 6J, which is correct since the ball's energy is potential when at rest. The kinetic energy before hitting the ground is also considered to be 6J, indicating energy conservation during the fall. The participant struggles with calculating the velocity upon impact and the velocity after the rebound, as well as understanding energy loss due to the rebound height being lower than the original drop height. The conversation emphasizes the need to apply energy conservation principles and clarify calculations for accurate results.
Hazim1214
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Homework Statement



[If a ball of mass (400g) falls from a height of (1.5m) towards the ground, and rebounds a height of (1m), find:

a) Initial Potential Energy
b) Kinetic Energy of ball before hitting the ground
c) Velocity at which it reaches the ground
d) The velocity at which it leaves the ground
e) Initial Kinetic Energy
f) Energy lost to it's surroundings]

Homework Equations



GPE = mgh
KE = 1/2mv^2 (I think this is relevant..)

and I don't know what else, that's the problem..

The Attempt at a Solution



a) = mgh = .4x10x1.5 = 6J?
b) Final KE = Initial GPE (I think...), so = 6J?
c) v = square root of 37?
d) no idea where to even start..
e) I think this is 0, because it doesn't move initially?
f) no idea where to start...

Anyone able to provide me some insight? Thanks.
 
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Hazim1214 said:

Homework Statement



[If a ball of mass (400g) falls from a height of (1.5m) towards the ground, and rebounds a height of (1m), find:

a) Initial Potential Energy
b) Kinetic Energy of ball before hitting the ground
c) Velocity at which it reaches the ground
d) The velocity at which it leaves the ground
e) Initial Kinetic Energy
f) Energy lost to it's surroundings]

Homework Equations



GPE = mgh
KE = 1/2mv^2 (I think this is relevant..)

and I don't know what else, that's the problem..

The Attempt at a Solution



a) = mgh = .4x10x1.5 = 6J?
Right. It's not moving initially, so all of its energy is potential.
b) Final KE = Initial GPE (I think...), so = 6J?
Right. Energy is conserved during the fall, so the initial potential energy is equal to the final kinetic energy.
c) v = square root of 37?
Not sure where this came from. Show us your calculations.
d) no idea where to even start..
e) I think this is 0, because it doesn't move initially?
You need to work this part the same way you did the first part, but this time you know the final potential energy. For part (e), you're supposed to find the speed the ball is moving as it starts its upward trajectory.
f) no idea where to start...

Anyone able to provide me some insight? Thanks.
After the bounce, it doesn't reach the same height it started at, so what does that tell you about the ball's energy?
 
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