N-D spring-mass damper total energy

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ashapi
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Homework Statement



I am trying to derive the total energy for an n-dimensional linear (Hookeian) spring-mass damper system and show that the total energy is either decreasing or constant.

Homework Equations


1D spring-mass damper equation
n-D spring-mass damper equation

The Attempt at a Solution



I started with the following force equation in 1D to describe the system:

(1) m[tex]\ddot{x}[/tex] + b[tex]\dot{x}[/tex] + kx = 0

Where:
m[tex]\ddot{x}[/tex] = Facc = m[itex]\frac{d^{2}x}{dt^{2}}[/itex]
b[tex]\dot{x}[/tex] = Fdamp (viscous friction) = C[itex]\frac{dx}{dt}[/itex]
kx = Fpotential (gradient of some potential) = [tex]\nabla[/tex]P(x)

So the equation becomes:

(2) -[tex]\nabla[/tex]P(x) - C[itex]\frac{dx}{dt}[/itex] = m[itex]\frac{d^{2}x}{dt^{2}}[/itex]

I then modeled the total energy as follows:

(3) Etot = P(x) + [itex]\frac{1}{2}[/itex]m[tex]\dot{x}[/tex]2

and

(4) [itex]\frac{dE}{dt}[/itex]= [tex]\nabla[/tex]P(x)[tex]\dot{x}[/tex] + m[tex]\dot{x}[/tex][tex]\ddot{x}[/tex]

In (4) I substituted m[tex]\ddot{x}[/tex] from (1) and got:

[itex]\frac{dE}{dt}[/itex]= [tex]\nabla[/tex]P(x)[tex]\dot{x}[/tex] + [tex]\dot{x}[/tex](-[tex]\nabla[/tex]P(x) - C[tex]\dot{x}[/tex])

=> -C[tex]\dot{x}[/tex]2

...which shows that total energy is either decreasing (|[tex]\dot{x}[/tex]| > 0) or constant ([tex]\dot{x}[/tex] = 0)

I then tried to derive the total energy for the n-dimensional case and relate it to an n-D force equation as I did above. To do this I looked at the 2D case and then generalized the formulas for kinetic and potential energy to n-D but I'm not sure if this was correct. Here are my kinetic and potential energy equations for 2D:
 
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My latex seems to bug out sometimes so if it looks weird please click on the source but let me continue...

KEtot,2D = [itex]\frac{1}{2}[/itex](m11[tex]\dot{x}[/tex]12 + m22[tex]\dot{x}[/tex]22 + m12[tex]\dot{x}[/tex]1[tex]\dot{x}[/tex]2)PEtot = [itex]\frac{1}{2}[/itex](m11[tex]{x}[/tex]12 + m22[tex]{x}[/tex]22 + m12[tex]{x}[/tex]1[tex]{x}[/tex]2)

I took the generalized forms to be:

KEtot,nD = [itex]\sum_{i=1}^{n}[/itex] (mii)[tex]\dot{x}[/tex]i2 + [itex]\sum_{j=1}^{n-1}[/itex] [itex]\sum_{k=j+1}^n[/itex] (mjk)[tex]\dot{x}[/tex]j[tex]\dot{x}[/tex]k

...and the same for PE with [tex]{x}[/tex] replacing [tex]\dot{x}[/tex].

My plan was to take the derivatives of these and replace the m[tex]\ddot{x}[/tex] terms with the force equivalences (as above). Is this right? I also can't think of how to make a generalized form of the force equation for an n-D vector.

Any help would be greatly appreciated.

Thanks,

ashapi
 
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