Naming Li & N Compounds: Li3N Explanation

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The discussion centers on the naming and formation of lithium nitride (Li3N) from lithium and nitrogen. Lithium has a +1 charge, while nitrogen can exhibit various oxidation states, commonly ranging from +5 to -3. The correct formation of Li3N involves the oxidation of lithium and the reduction of nitrogen, where six lithium atoms are required to convert nitrogen gas (N2) to nitride ions (N3-). The notation (2) in the formula 2Li3N indicates that two moles of lithium nitride are produced in the reaction. The participants clarify the electron transfer process, emphasizing that lithium is oxidized while nitrogen is reduced, correcting earlier statements about the reaction's stoichiometry. Overall, the conversation highlights the importance of understanding oxidation states and electron transfer in chemical reactions.
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Hey, I was just wondering about naming this compound

Lithium and Nitrogen. I know Li has a +1 charge but Nitrogen can have a bunch. How do I know what one to pick. Also my teach has this written for the correct answer (2)Li3N... what is that (2) out there for?


Thanks
 
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Lithium and nitrogen gives lithium nitride, Li3N. I have no idea what (2) means here, but according to redox chemistry, we can find the required coefficients.

Lithium:from Li^0 to Li^+
Nitrogen: from N_2 to N^{3-}

6~Li~+~N_2 \xrightarrow {heat} 2~Li_3N

Look for Faraday's technique for synthesizing this compound.
 
Score thanks.
 
Oh yeah Umm question about this: For instance N have electron charges from +5 - (-1) How do you know what one to write down when combining it with an element.
 
Hello, I don't think nitrogen reduces from 5+ to 1- in any reaction, the most popular oxidation numbers for nitrogen are 5+, 4+, 2+, 1+, 0, and 3-. I may be wrong of course, but at least in your question, nitrogen changes from 0 to 3-; lithium is oxidized to its only oxidation state, 1+.

The order is as follows, first lithium is oxidized and electrons go out from it, and nitrogen gets electrons to reduce. As six electrons are needed to convert N2 to 2N3-, six moles of Li is needed as 6Li \rightarrow 6Li^+~+~e^-.
 
A false statement about my last post:

My last LateX reaction is wrong, as it should be 6Li \rightarrow 6Li^++6e^-. Sorry for seeing this too late.
 
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