Calculating Capacitance for Pulsed Nitrogen Laser Design: Tips and Tricks

  • Thread starter Thread starter TrolliOlli
  • Start date Start date
  • Tags Tags
    Capacitance
AI Thread Summary
To calculate the capacitance needed for a pulsed nitrogen laser, the energy requirement per pulse is 96 J. The breakdown voltage of air, approximately 3 million volts per meter, is essential for determining the voltage across the spark gap of 0.93 cm. Using the formula for potential energy, U = 1/2 CV², the capacitance can be derived once the voltage is known. After ionization, the resistance in the spark gap decreases significantly, allowing the capacitor's energy to discharge effectively. Understanding these parameters is crucial for successful laser design.
TrolliOlli
Messages
13
Reaction score
0

Homework Statement


You are part of an engineering research team that is designing a pulsed nitrogen laser. To create the high energy densities needed to operate such a laser, the electrical discharge from a high-voltage capacitor is used. Typically, the energy requirement per pulse (i.e., per discharge) is 96 J. Estimate the capacitance required if the discharge is to create a spark across a gap of about 0.93 cm. Assume that the dielectric breakdown of nitrogen is the same as the value for normal air.

I honestly am completely lost.

I know C = Q/V = Q/Ed and also the potential energy U = 1/2 CV^2 but I don't know what I can do with the variables I'm given to get either V or E.
 
Physics news on Phys.org
This brings me back - I built a nitrogen laser in 1975 and used it's UV pulses to stimulate an experimental dye laser.

A high voltage is required to ionize the air in the spark gap; you'll need to look that up, perhaps in Wikipedia. Once it is ionized, the resistance is quite low and you can assume all the energy in the capacitor goes into the discharge. So your U = 1/2 CV² will do the job once you know the voltage required.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top