Need clarification of projectile motion

AI Thread Summary
The discussion focuses on a physics problem involving projectile motion, specifically calculating the flight time and speed of a bullet that hits a target 50 meters away, 2 cm below the aim point. Participants express confusion over the conversion of 2 cm to -0.2 m for the vertical displacement (y1). The importance of visualizing the problem with a diagram is emphasized to clarify the variables involved. Additionally, there is a side discussion about the time it takes for an object to fall 2 cm, highlighting the need for accurate unit conversion. Understanding these concepts is crucial for solving projectile motion problems effectively.
rashad764

Homework Statement


A rifle is aimed horizontally at a target 50m away. The bullet hits the target 2.0 cm below the aim point. What was the bullets flight time and speed.
t0=0s
x0=0m
y1=-0.2m
x1=50m
vox=v0
voy=0m/s

Homework Equations


Y1=1/2ay^2+v0t+y0
x1/t=vox

The Attempt at a Solution


My teacher went over this problem already, but I'm trying to understand how -0.2m is obtained for y1.
 
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rashad764 said:
My teacher went over this problem already, but I'm trying to understand how -0.2m is obtained for y1.
What was the origin? It's fairly useless to try to do these problems without drawing a diagram showing what's happening and what each variable represents.
 
rashad764 said:

Homework Statement


A rifle is aimed horizontally at a target 50m away. The bullet hits the target 2.0 cm below the aim point. What was the bullets flight time and speed.
t0=0s
x0=0m
y1=-0.2m
x1=50m
vox=v0
voy=0m/s

Homework Equations


Y1=1/2ay^2+v0t+y0
x1/t=vox

The Attempt at a Solution


My teacher went over this problem already, but I'm trying to understand how -0.2m is obtained for y1.
How long does it take a rock to drop 2cm when released?

And 0.2m is not equal to 2cm...
 
berkeman said:
How long does it take a rock to drop 2cm when released?

And 0.2m is not equal to 2cm...
thanks
 
rashad764 said:
thanks
You are welcome. What is your answer to my first question? :smile:
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »

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