Need help - Average Speed-Interval Problem

Thread starter junesmrithi
Start date Feb 5, 2007
Tags

Average

AI Thread Summary

To find the average speed of the caiman, first calculate the total distance, which is 160 meters plus 310 meters, totaling 470 meters. Next, determine the time taken for each segment: 16 seconds for the first 160 meters at 10 m/s and 77.5 seconds for the 310 meters at 4 m/s, resulting in a total time of 93.5 seconds. The average speed is then calculated by dividing the total distance by the total time, yielding an average speed of approximately 5.03 m/s. This problem illustrates the importance of understanding average speed calculations in varying conditions. The solution emphasizes the need for careful time and distance analysis in speed-related problems.

Feb 5, 2007

junesmrithi

need help ASAP- Average Speed--Interval Problem

Average Speed--Interval Problem

Question: A caiman swims 160 meters at a speed of 10 m/s. It then enters a stream and slows to 4 m/s for 310 meters. What is the average speed of this cousin of the crocodile?

Equation given: Average speed is total distance divided by total time

Physics news on Phys.org

Feb 6, 2007

andrevdh

Well, can you calculate the total distance covered with the given information?

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »