Need Help- Centripetal car problems, finding the angle

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SUMMARY

The discussion focuses on calculating the banking angle for a curve with a radius of 100 meters, allowing a car to navigate at a speed of 90 km/h without relying on friction. The key equations derived include the centripetal force equation, Fc = Fnsinθ, and the vertical equilibrium equation, Fg = Fncosθ. The user expresses confusion regarding the application of these equations in a non-inertial reference frame, emphasizing the need for clarity in separating forces acting parallel and perpendicular to the road.

PREREQUISITES
  • Understanding of centripetal force and its role in circular motion
  • Familiarity with trigonometric functions and their application in physics
  • Knowledge of Newton's laws of motion, particularly in non-inertial reference frames
  • Basic skills in solving equations involving forces and motion
NEXT STEPS
  • Study the derivation of the banking angle formula for circular motion
  • Learn about non-inertial reference frames and the effects of fictitious forces
  • Explore the concepts of frictionless motion in physics
  • Review examples of centripetal acceleration and its applications in real-world scenarios
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of banking angles in practical applications.

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Homework Statement



Find the angle at which a curve of radius 100m, should be
banked in order that a car moving at a speed 90 km/h will not
need any frictional force to round it

The Attempt at a Solution


Alright so what i did was, i made two equations...
Fc=Fnsinθ
ma=mgsinθ
v^2/r=gsinθ this is the horizontal force toward the centre of the circle.

And now for the vertical equilibrium
Fg= Fncosθ is this correct i am not understanding how i would do this?

AND THE REST i am really confused about what to do...
 
Last edited:
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Try writing the equations for parallel and perpendicular to the road.
Just keep in mind that you aren't dealing with an inertial reference frame. The [itex]F_c[/itex] pointing in that is your centripetal force, is the same as a centrifugal force pointing out in this reference frame.
 
Who r u Lola. You go to my school cause all of your questions you're asking are from an assignment. Message me back, cause i want to compare answers with u.
 

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