- #1
maxfails
- 11
- 0
The equation is
y'' + 4y' + 4y = (3 + x)e-x
and initial conditions y(0) = 2, y'(0)=5so from the associated homogenous equation
I think the fundamental set of solutions is {e^-2x, xe^-2x} and so yc would be
Yc = c1e-2x + c2xe-2x
but now I don't know how to get Yp, particular solution or what form they are.
Do I need to expand the (3 + x)e-x, and then solve for 2 different particular solutions?
so solve for a Yp when y'' + 4y' + 4y = 3e-x as well as
y'' + 4y' + 4y = xe-x, or do I only need to solve for 1 Yp?
y'' + 4y' + 4y = (3 + x)e-x
and initial conditions y(0) = 2, y'(0)=5so from the associated homogenous equation
I think the fundamental set of solutions is {e^-2x, xe^-2x} and so yc would be
Yc = c1e-2x + c2xe-2x
but now I don't know how to get Yp, particular solution or what form they are.
Do I need to expand the (3 + x)e-x, and then solve for 2 different particular solutions?
so solve for a Yp when y'' + 4y' + 4y = 3e-x as well as
y'' + 4y' + 4y = xe-x, or do I only need to solve for 1 Yp?