Need help- Force of friction in a circle.

AI Thread Summary
To determine the force of friction necessary to keep a 45-kg worker from falling off a merry-go-round while moving at 4.1 m/s, the relevant equations include centripetal acceleration and frictional force. The radius (r) of the circular path is 6.3 m, which is essential for calculating the centripetal acceleration. The derived equation for friction, μ = v²/(rg), indicates that both the speed and radius are crucial in finding the coefficient of friction needed. Clarification on the role of the radius in the equations is sought to properly approach the problem. Understanding these relationships is key to solving the friction force requirement.
Socom
Messages
1
Reaction score
0

Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?


Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r


The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.
 
Physics news on Phys.org
Socom said:

Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?

Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r

The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.

You got the right equation:

\mu = \frac{v^2}{rg}

now tell me... what does the r mean in:

A_c = \frac{v^2}{r}
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Back
Top