How Do Helicopters Fly Using Bernoulli's Principle?

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Helicopters fly primarily due to the principles of aerodynamics, particularly Bernoulli's principle, which explains how air pressure differences create lift. The rotor blades function similarly to wings, generating lift as they spin and creating lower pressure above the blades compared to the higher pressure below. For a deeper understanding, resources such as HowStuffWorks and helicopter-specific websites are recommended. The discussion emphasizes the importance of clarifying the level of detail needed for a comprehensive explanation. Overall, understanding the mechanics of helicopter flight involves grasping the relationship between rotor movement and aerodynamic forces.
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i need to understand how how helicopters work,anyone know?
 
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catriona said:
i need to understand how how helicopters work,anyone know?
Welcome to PF,

To what level do you need to go? Is it for a project? Have you tried searching on the Internet? Perhaps, this would be more appropriate in the engineering forums and one of the mentors would be kind enough to move it?
 
If you have specific questions, ask away. I echo Hoot's question. To what level of detail do you want to go?

Here's a pretty good site.
http://www.helicopterpage.com/
 
Well, the blades are like wings, and they spin round, and the helicopter goes up.


Otherwise, same answer as the others gave.
 
Think Bernoulli.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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