Need help solving an inequality.

[Checkfate]

I figured out the answer to the question I originally posted in this thread, but, I have another.

I am trying to solve 2+x^{\frac{-3}{2}}>0

I end up with x>(-2)^{\frac{-2}{3}} by just putting the 2 on the other side and solving. This is not the right answer though... what am I doing wrong? Thanks

Thats a 2+x^(-3/2) btw. (for the top tex) and a (-2)^(-2/3) for the bottom tex.

 

[radou]

Try to look at the inequality f(x) > 0, where f(x) = 2 + x^(-3/2). Analyze the function.

 

[Checkfate]

Okay, I guess it makes more sense to do it that way :).

Since there is a x under a square root sign, the domain is [0,inf) and since the squareroot is always positive, the function is always > 0 :). Thanks,