Need help to find average velocity and pressure drop in duct

AI Thread Summary
To determine the average velocity and pressure drop in a duct, the average velocity of air is calculated using the volume flow rate of 5000 l/s and the duct's cross-sectional area, resulting in an average velocity of 13.88 m/s. The velocity head is computed as 9.83 meters of air column, while the frictional losses over the 87-meter duct at 3 Pa/m total 267 Pa. The required fan pressure to overcome these losses and maintain airflow is calculated to be 110.63 KPa. Additionally, the fan power needed to achieve this pressure and flow rate is approximately 555 kW. Accurate calculations are essential for effective duct design and fan selection.
mchi6aa2
Messages
2
Reaction score
0

Homework Statement



1. the average velocity of the air to meet the required volume flow rate,
2. the pressure a fan needs to produce to overcome the frictional losses in the duct,

2. Relevant Information

Duct size - 600 mm x 600 mm which operates at 3 Pa/m.
The air path is 87 meters from intake to discharge including allowances for grilles, bends and dampers.
The pressure drops per meter are for the required volume flow rate of 5000 l/s. Average velocities in the duct can be calculated by considering the volume flow rate and cross sectional area of the ducts.

Please help. Thanks

Danny
 
Physics news on Phys.org
Thats the way I did. I am not sure is it right or wrong:

First , Head required to overcome friction Losses and to maintain
velocity head is to be calculated.

Q= 5000 l/s = 5 m³ /s , A= 0.6 * 0.6 = 0.36 m² , Av . Velocity = Q/A =13.88 m/s

Velocity head = V²/2g = 9.83 m of air coloumn ,
frictional head to overcome by the fan = 3*87=267 Pa

Fan pressure = 1.145 * 9.83 * 9.8 KPa + 267 Pa = 110.63 KPaFan power required = PQ = 110.63 * 5 = 555 Kw
 
Back
Top