Finding the Value of B in a Simple Equation

  • Thread starter Thread starter abot
  • Start date Start date
AI Thread Summary
To find the value of B in the equation (1.5999A)^2 = B^2 + A^2, the user is struggling to match their answer with the book's solution of 1.247. It is suggested that two equations are needed to solve for two variables, and clarification is given that the book's answer might actually be "1.247A." The discussion emphasizes simplifying the equation by subtracting A^2 from both sides and then taking the square root. Ultimately, the focus is on correctly manipulating the equation to find B.
abot
Messages
17
Reaction score
0
HI, i can't solve this equation. I am solving for B the answer in the book does not match mine. PLZ help.


(1.5999A)^2= B^2 + A^2

the answer in the book is 1.247
 
Physics news on Phys.org
What is A? You need two equations to solve for two variables.
 
thats all i have. the parent equation was

.0251A=.0157sqrtB^2 + A^2
 
Are you absolutely sure the answer in the book isn't "1.247A"? :wink:

Anyway, just subtract A^2 from both sides and take a square root to get that answer.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top