Need help with a Slope problem

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The discussion revolves around solving a slope problem involving a plane's forces, specifically calculating lift and resistance while maintaining a constant velocity at a 30-degree angle. The user sets up equations for the forces in both the x and y directions but struggles with too many variables and the orientation of the axes. Key concepts include that lift acts vertically and balances weight, while thrust and drag are aligned with the aircraft's motion. The user concludes that for cruising at constant velocity, lift equals weight and thrust equals resistance. The problem is ultimately resolved with the provided insights.
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Need urgent help with a Slope problem

Homework Statement


A plane is traveling at a constant velocity at 30 degrees above the horizontal. Weight (W)=86 500 N; thrust (T)=103 000 N. Find the lift force and the resistance force (L= normal force, R=friction) without shifting the cartesian coordinate system


Homework Equations


sum of the forces in the x=ma, sum of the forces in the y=ma. a=0.


The Attempt at a Solution


I have set up the problem with x dir: T cos(30) - L sin(30) - Rcos(30)=ma and y dir: W - T sin(30) + L cos(30) - R sin(30)=ma and ma=0. R in the y dir is negative. Is R in the y dir equivalent to mg? I'm stuck with too many variables in my equation. Any help would be greatly appreciated.
 
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W = mg and it acts directly downward. Lift acts vertically. Resistance (Drag) acts in opposition to motion, or against the thrust.

See - http://www.grc.nasa.gov/WWW/K-12/airplane/forces.html

http://www.grc.nasa.gov/WWW/K-12/airplane/presar.html
Since the fluid is in motion, we can define a flow direction along the motion. The component of the net force perpendicular (or normal) to the flow direction is called the lift; the component of the net force along the flow direction is called the drag. These are definitions. In reality, there is a single, net, integrated force caused by the pressure variations along a body. This aerodynamic force acts through the average location of the pressure variation which is called the center of pressure.

By convention take T and L to be positive, and R and W (= mg) to be negative.

See also - http://www.grc.nasa.gov/WWW/K-12/airplane/cruise.html
which gives the condition for straight (horizontal) flight.
 
I understand the concepts as you explained them. My problem is that I connot tilt the x,y axis to solve the problem with information I have. Therefore, I am trying to use trig functions to solve for T and R, which are not directly on the x and y axis. The only compnent that is on the x and y-axis is W. Since R in the y direction is negative, can I use mg to solve R (in the y direction) sin (30)?
 
Anyone?
 
What does the text say about lift (L). According to NASA's site, L is vertical and balance against weight. The thrust (T) and drag or resistance (R) are oriented along the axis of the aircraft.

So that would imply L = W and T = R for cruising or constant velocity.
 
Thank you! That is exactly the information I needed! The problem worked out great.
 
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