Need help with basic specific heat capacity problem

Click For Summary

Homework Help Overview

The problem involves determining the specific heat capacity of a metal by analyzing the temperature changes in a system consisting of the metal, an insulated container made of the same metal, and water. The scenario includes specific masses and initial temperatures, leading to a final temperature after heat exchange.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the heat transfer equation and the algebra involved in solving for the specific heat capacity. There is a focus on ensuring the correct application of the equation and checking for algebraic errors.

Discussion Status

Some participants have provided feedback on the algebraic steps taken by the original poster, suggesting that there may be mistakes in the calculations. There is an ongoing exploration of the correct approach to solving for the specific heat capacity.

Contextual Notes

Participants are working within the constraints of the problem as stated, including the known specific heat capacity of water and the requirement to use the heat transfer equation. There is an acknowledgment of potential errors in the algebraic manipulation of the equation.

lilmul123
Messages
39
Reaction score
0

Homework Statement



The specific heat of a certain metal can be determined by measuring the temperature change that occurs when a piece of the metal is heated and then placed in an insulated container that is made of the same material and contains water. Suppose the piece of metal has a mass of 86 g and is initially at 100°C. The container has a mass of 162 g and contains 504 g of water at an initial temperature of 20.0°C. The final temperature is 21.4°C. What is the specific heat of the metal?

Homework Equations



Q = mc(deltaT)
Q1 + Q2 + Q3 = 0

4.18 kJ/kg*K is the known capacity of water.

The Attempt at a Solution



I set c equal to the specific heat capacity I'm looking for. Q1 is the metal going into the bucket, Q2 is the metal of the bucket, and Q3 is the water itself. Since Q1 and Q2 are the same metal, their c's are the same.

My equation looks like this where the specific heat capacities are in kJ/kg*K:

(.086)(c)(-78.6) + (.162)(c)(1.4) + (.504)(4.18)(1.4) = 0

Solving for c gives me 2.214 kJ/kg*K which is incorrect. Have I missed a step?
 
Physics news on Phys.org
Check your algebra. I get 0.45 kJ/kg*K using your equation.
 
lilmul123 said:
(.086)(c)(-78.6) + (.162)(c)(1.4) + (.504)(4.18)(1.4) = 0

Solving for c gives me 2.214 kJ/kg*K which is incorrect. Have I missed a step?

Check your algebra again when you solve for c. It looks like you may have made a mistake. I'm getting about 0.45.
 
Oh geez, I divided by the wrong side in my last step of the algebra. Thanks!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
988
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K