Need Help with Integration for Solving ODE

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Homework Help Overview

The discussion revolves around solving a first-order ordinary differential equation (ODE) given by \(\frac{dy}{dx}=y^2-1\) with an initial condition \(y(0)=3\). Participants are exploring integration techniques to solve the equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the transformation of the ODE into a separable form and the subsequent integration of \(\int \frac{dy}{y^2-1}\). There is mention of using partial fractions as a method for integration, and one participant suggests factoring the expression to facilitate this process.

Discussion Status

Some participants have provided hints and guidance regarding the integration technique, particularly focusing on partial fractions. There appears to be ongoing exploration of the integral, with one participant indicating they have arrived at an answer.

Contextual Notes

There is a reference to a similar integral being discussed in another thread, suggesting a broader context of related problems. The initial condition and the specific form of the ODE are also noted as important elements of the discussion.

The-Mad-Lisper
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Homework Statement


\frac{dy}{dx}=y^2-1
y(0)=3

Homework Equations


\frac{dy}{dx}=f(y) \leftrightarrow \frac{dx}{dy}=\frac{1}{f(y)}

The Attempt at a Solution


\frac{dx}{dy}=\frac{1}{y^2-1}
dx=\frac{dy}{y^2-1}
\int dx=\int \frac{dy}{y^2-1}+C
x=\int \frac{dy}{y^2-1}+C
How do I integrate \int \frac{dy}{y^2-1}?
 
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The-Mad-Lisper said:

Homework Statement


\frac{dy}{dx}=y^2-1
y(0)=3

Homework Equations


\frac{dy}{dx}=f(y) \leftrightarrow \frac{dx}{dy}=\frac{1}{f(y)}

The Attempt at a Solution


\frac{dx}{dy}=\frac{1}{y^2-1}
dx=\frac{dy}{y^2-1}
\int dx=\int \frac{dy}{y^2-1}+C
x=\int \frac{dy}{y^2-1}+C
How do I integrate \int \frac{dy}{y^2-1}?
Partial fractions. See https://www.physicsforums.com/insights/partial-fractions-decomposition/ if you are uncertain about this technique.
 
Hi Mad:

I will give you a hint. think about factoring y2-1 = f1(y) × f2(y).
Then think about finding A and B such that 1/(f1 × f2) = A/f1 + B/f2.

Hope this helps.

Regards,
Buzz
 
Thanks, I got the answer.
 
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