Need Help with Newton's 1st and 2nd Laws

  • Thread starter Thread starter kenau_reveas
  • Start date Start date
  • Tags Tags
    Laws
AI Thread Summary
In the discussion about Newton's 1st and 2nd Laws, participants focus on determining when an object can move at a constant velocity of 256 m/s under various force scenarios. The key point is that for an object to maintain constant velocity, the net force acting on it must equal zero, meaning all applied forces must balance each other out. Examples are provided to illustrate this concept, such as comparing forces of different magnitudes to see if they can cancel each other. The importance of drawing a free body diagram (FBD) is emphasized to visualize the forces involved. Clarification is sought on how to approach similar problems in the future.
kenau_reveas
Messages
39
Reaction score
0
Need Help with "Newton's 1st and 2nd Laws"

In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly move at a constant velocity of 256\;{\rm m/s}?

The forces applied are as follows:

1. 2 N; 2 N
2. 200 N; 200 N
3. 200 N; 201 N
4. 2 N; 2 N; 4 N
5. 2 N; 2 N; 2 N
6. 2 N; 2 N; 3 N
7. 2 N; 2 N; 5 N
8. 200 N; 200 N; 5 N

please help me out here.
 
Physics news on Phys.org
FBD FBD...sum up all the forces and equate to 0 since constant velocity
 
FDB means options F, D, and B? that's it.i am not able to understand the question. can you please simplify so that i can understand and slove smiliar kind of questions in future.
 
The thing to figure out in each case is whether it is possible for the forces to be oriented in such a way that they add to zero. (Here's an example: If two forces act on an object, one 10 N the other 100 N, can they possibly cancel each other? No.)
 
FBD=free body diagram where u draw all the forces acting on the object.alrite suppose there is an upward force 100N and a downward force 200N and the object is moving at constant speed. so taking down as negative, it will be( summation force)100-200=m(0)..so there is a net force of 100N downward
 
i really don't know how to do it..i would really appreciate if anyone can help me with the answer..
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top