Need stress value of aluminium for project work

AI Thread Summary
Aluminium 6061-T has a yield strength of 276 MPa, while the pressure at 10 meters underwater is 99 kPa. It is noted that some deformation will occur under load, as all materials deform to some extent. Finite Element Analysis indicates a maximum von Mises stress of about 40 MPa for the vessel design. Based on this stress level, the vessel could theoretically withstand depths of approximately 69 meters without safety factors. The discussion emphasizes the importance of understanding material properties and pressure effects for underwater applications.
Hakuyu
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Im not a physics student but I really need to prove that aluminium will not deform 10m underwater
Summary: I am not a physics student but I really need to prove that aluminium will not deform 10m underwater

Hi I am doing a project of a product which will sink underwater.
It will be a sealed cylindrical vessel, length 2m, width 1m, thickness 0.02m.
Aluminium 6061t will be used with a yield strength of 276MPa.
Pressure of water 10m underwater will be 99kPa.

If you can provide me with the stress value of aluminium please also provide me with your designation as I need to cite it with your approval.

Thank you so much !
 
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Hakuyu said:
Summary: I am not a physics student but I really need to prove that aluminium will not deform 10m underwater

Summary: I am not a physics student but I really need to prove that aluminium will not deform 10m underwater

Hi I am doing a project of a product which will sink underwater.
It will be a sealed cylindrical vessel, length 2m, width 1m, thickness 0.02m.
Aluminium 6061t will be used with a yield strength of 276MPa.
Pressure of water 10m underwater will be 99kPa.

If you can provide me with the stress value of aluminium please also provide me with your designation as I need to cite it with your approval.

Thank you so much !
Is this for a school project? If so, which class?

If not, what is the overall project that you are working on? And what do you mean by "cite it with your approval"? Approval for whom?
 
Sorry to disappoint you, but there will be some deformation assuming that the pressure inside is different from that outside. Everything has some deformation under load.
 
In „Roark’s Formulas for Stress and Strain” book you can find formulas for stress in cylindrical pressure vessels subjected to external pressure. But I performed Finite Element Analysis assuming flat bottom and maximum von Mises stress result is about 40 MPa.
 
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1570796574071.png


Using the above graph can I assume his aluminium vessel is good to about 4000m depth?

FEAnalyst said:
In „Roark’s Formulas for Stress and Strain” book you can find formulas for stress in cylindrical pressure vessels subjected to external pressure. But I performed Finite Element Analysis assuming flat bottom and maximum von Mises stress result is about 40 MPa.
 
Spinnor said:
Using the above graph can I assume his aluminium vessel is good to about 4000m depth?

Based upon the the flat end closure plate's above determined 40 MPa stress at the 10 m depth and the stated maximum allowed S yield of 276 MPa for the material, the maximum depth = 10 x 276/40 = 69 m without any safety factor.
 
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