Negative Buckling: What Are the Conditions?

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Negative buckling (B^2) is not possible under any conditions, as buckling relies on physical parameters that cannot be negative, such as sphere radius and diffusion coefficient. The discussion clarifies that mechanical buckling differs from buckling related to neutron flux in nuclear reactors. A negative B^2 indicates a subscritical system, defined by the relationship between neutron multiplication factors and absorption cross-sections. Specifically, B^2 becomes negative when the neutron multiplication factor (k∞) is less than one or when the absorption cross-section exceeds the product of neutron flux and fission cross-section. Overall, geometric buckling cannot be negative, reinforcing the distinction between these concepts.
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Under what conditions would negative buckling (B^2) be possible?
 
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Never. Buckling is a function of physical parameters (sphere radius, reaction cross-sections, diffusion coefficient), none of which can ever be negative.
 
Nidum said:
Buckling of a structure (mechanical analysis) is not the same as 'buckling' with respect to the neutron flux in a nuclear reactor.

I believe B2 < 0 implies the system is subscritical.

Let B2 = (νΣf - Σa)/D = (k - 1)/L2, then the buckling is negative if k < 1, or Σa > νΣf.

Ref: http://www.nuceng.ca/br_space/2015-09_4d03_6d03/learning_modules/11_flux_shape_in_various_reactor_geometries.pdf

Geometric buckling would not be negative.
 
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