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From the diagram above, there are two types of wires a straight wire and a non-straight wire(zig-zag shaped wire), that are both placed inside a magnetic field(B), and have current flowing in both of them as well. The straight wire will experience a force and will move towards the left as marked(F-direction), while as the zig-zag wire will have the force dependent on the angle and Lorentz force, since there are a couple of bends on the zig-zag wire, there will be a force at an angle perpendicular to the current flow,as marked(purple arrows), the y-axis of each bend cancels out with the upper wire only leaving the x-axis remaining. Correct?

Depending on the angle(in degrees) the force on that zig-zag wire would be:

$$F = IL \times B$$ - which is the same as the straight wire,

**however**, $$F_z = F_L \times \cos(x°)$$

Where [tex] F_L [/tex] is the Lorentz force of the zig-zag wire, and [tex] F_z [/tex] is the net-force of the zig-zag shaped wire's x-axis if the angle is known.

Is this correct? I don't think the second wire is equal to the straight wire, because there are some opposing forces that cancel each other out(y-axis) due to the current flow being opposite, and leaving some force remnant that is the x-axis.

**NOTE:** Both wires are the same in Length, and have the same current flow, and placed in the same magnetic field.