Net Magnetic Field at the Center of a Loop and X Distance Away From a Wire

AI Thread Summary
The discussion focuses on calculating the radius of a loop given that the net magnetic field at its center is zero, with the current in the loop being 6.61 times that of a straight wire. The relevant equations for magnetic fields from a straight wire and a loop are provided. The user attempts to express the magnetic field in terms of the loop's radius but becomes uncertain about their calculations. A clarification is made regarding the orientation of the magnetic fields produced by the loop and the straight wire, emphasizing that they are indeed perpendicular. The conversation highlights the complexities involved in solving the problem and the need for careful consideration of magnetic field directions.
BornSurvivor
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Homework Statement


https://fbcdn-sphotos-a.akamaihd.net/hphotos-ak-prn1/553004_1959186995753_1725123128_934768_456680196_n.jpg
In case the words are too small:
I2= 6.61I1
The net magnetic field at center of loop is 0.
I'm looking for the radius of the loop

Homework Equations


for straight wire: B=(u0*I)/(2\pi*r)
for loop: B= (u0*I)/(2*r)

The Attempt at a Solution


So, since the two magnetic fields are perpendicular to each other: √(B12+B22)=0
I tried to find H in terms of R by using the right hand rule. I2/I1=(B2*H*\pi)/(B1*R) so H= -(6.61R/\pi)
But now I'm stuck, and I don't know if my work so far is even right.
 
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Hi BornSurvivor! :smile:

(pleeeeeease don't post such wide images! :redface:)
BornSurvivor said:
So, since the two magnetic fields are perpendicular to each other …

No, a loop current's magnetic field goes along the axis of the loop,

and a straight line current's magnetic field goes in loops around the line. :wink:
 
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