mopar969
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mopar969 said:Please see attachment for the problem. I used the rules for parallel and series resistors to find a total resistance in the network of 4560/59 ohms and then found a current of 59/152 amps through the 20 ohm resistor in the original problem. Am I correct?
mopar969 said:I added the 10 ohm resistors in series which makes 20 ohms and the three 60 resistors in parallel made 20 ohms. Then the 2 20 ohms resistors are in parrallel which makes 10 ohms. Then the 40, 10, 50, and 20 ohm resistors are in series and make 120 ohms which is then parralel to the 240 ohm resistor.
Maybe I mad a mistake some where let me know. Thanks.