urtalkinstupid said:
If neutrinos don't interact with the the electromagnetic forces, explain how they detect them? They interact by collision. This collision with an electron promotes decay. Through this decay a blue light cone is emitted. This is how neutrinos are detected, through interaction with electrons.
Neutrinos interact only via the weak force. They are not electrically charged, and thus
cannot participate in electromagnetic interactions. They are detected in heavy-water experiments by their interaction with neutrons. Taken from the SNO experiment's website at http://www.sno.phy.queensu.ca/sno/sno2.html:
As the neutrino approaches the deuterium nucleus a heavy charged particle of the weak force (called the W boson) is exchanged. This changes the neutron in deuterium to a proton, and the neutrino to an electron. The electron, according to mechanics, will get most of the neutrino energy since it has the smaller mass (just as when a gun is fired, the bullet, being lighter, gets most of the energy). Due to the large energy of the incident neutrinos, the electron will be so energetic that it will be ejected at light speed, which is actually faster than the speed of light in water. This causes the optical equivalent of a "sonic boom", where a "shock wave of light" is emitted as the electron slows down. This light flash, called Cherenkov radiation, is detected by the photomultiplier tubes (PMTs); the amount of light is proportional to the incident neutrino energy.
I will
again note that
collisions, in the microscopic sense, involve force interactions. If a particle, like the neutrino, only couples to the weak force, then the only collisions it can participate in involve the weak force.
There is no such thing as "touching," or "contact" in the microscopic realm.
urtalkinstupid said:
ArmoSkater87, positrons are what are theorized to make up part of the proton. When a collision occurs, this positron breaks off the proton and becomes the anti-particle to the electron.
Once again, this is false. How many times do we need to correct you? Positrons are absolutely not involved inside protons in any way at all.
Entropy, we all know that you think space-time curvature is gravity. So, you just think gravity is a geometric effect? Wouldn't space-time curvature throw out gravity as one of the fundamental forces? As you said previously, "space-time curvature isn't a force." So, there are only three fundamental forces?
Indeed, that is the state of things at the moment. There is the standard model, which is an excellent model of electromagnetism and the strong and weak forces. Gravity is the odd-ball. It does not behave as a gauge theory (at least not in an obvious way) as do the other three. Physicists are working on different ways of unifying gravity with the other three forces, but no one knows is that will ever happen. It is possible that gravity will always be regarded as fundamentally different than the other three forces.
Brad Ad23, "gravitational" lensing can be explained int he push theory. Take a beam of light, it is approaching a dense object. This dense object absorbs neutrinos, allowing less to pass through. The beam of light is over the dense object. It is being hit by more neutrinos on the top than bottom. This cause the light beam to bend at an angle.
Neutrinos do not interact with photons, because neutrinos are not electrically charged. Your theory of neutrinos cannot explain the gravitational deflection of light, period.
Neutrinos are all over. Since they travel at relativistic speeds, they interact with us constantly. If they pass through the earth, they do not cancel the affect of the sun. The neutrinos that pass through are outnumbered by the ones from the sun. The sun merely overpowers the nuetrinos that pass through. Net force is positive. Weigh is simply a term associated with the pull theory of gravity. The push theory does not regard weight. Neutrino direction is uniform until they go through emission and absorption. This alters the direction of the neutrino flow.
Since the neutrinos from the sun outnumber the neutrinos from every other source, the necessary conclusion is that the Sun's neutrinos would push you into the Earth during the daytime, and push you off it at night. Since this doesn't match observations, it must be wrong.
They don't "know" when to push in one direction. The push in all directions.
You just said they did not. You said the vast majority of them come from the Sun, which indicates that the vast majority of the force is in the direction of the Sun. Since my bathroom scale indicates I weigh the same both at night and during the daytime, it would indicate that somehow the
entire universe is conspiring to fire its neutrinos at me at just the right times.
You're also missing a huge part of this problem: if the vast majority of the neutrinos are from the Sun, then the force on both my body and the Earth as a whole is equal. Rather than my body being pushed into the Earth, both my body and the Earth would be equally pushed away from the Sun. As a result, we would all be weightless.
Emission and absorption is what makes a difference in the forces of neutrinos interacting. So, density is an ultimate factor determining emission and absorption. I've recently found a site that explains orbit through neutrinos interaction. Although, it is limited to the Earth moon system of orbiting. I'll be happy to give you the site, if you want it.
The density of Mercury is close to the density of iron. The density of Saturn, however, is lower than that of water. They both orbit the same star in essentially perfectly concentric orbits. How do you explain this?
Dark matter is simply a pushing force. Neutrinos are what make up hot dark matter as beatrix kiddo said.
We'll probably not take your word for it.
Let's put emphais on ALMOST. Not ALL forces over a distance are proportional to the inverse of distance squared. Neutrinos do not have to expand on the surface of a sphere. Light does, neutrinos don't.
Neutrinos are particles, yes? So if the Sun makes, say, 10
10 of them per second, and they spread out in every direction uniformly from the Sun, there are 10
10 of them in contained in every 300,000 km thick concentric shell around the Sun, yes? The volume of these shells increases as the square of its radius. Thus, there must be fewer neutrinos per unit volume as you move away from the Sun. Are you proposing some novel new mechanism that would allow neutrinos to avoid this obvious problem?
Neutrinos are said to interact through weak forces. What says that they can't interact with each other? Are they able to absorb each other energy, increasing their size? Oscillate as a consequence of this absorption?
They can interact with each other, but the cross-section for such an interaction is so low that it's neglible. They cannot absorb energy, because they are not composite particles and have no internal modes in which to store that energy. The only energy they can have is kinetic energy. They do not increase in size, and they do not "oscillate."
As for the response on how neutrinos would account for opposite space-time curvature. Think of a hyperbola. This would account for opposite space-time curvature. Everything is pushed towards the center still. Pull allows everything to fall towards the center. It's the same thing except opposite.
A... hyperbola? I'm still looking forward to the aliens in spandex and the tractor beams. I bet the captain will have sex with one of the aliens again!
- Warren
