(Newton's 2nd & 3rd laws) finding mass

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To find the mass suspended by two cables at angles of 30° and 60° with tensions of 24.5 N and 42.7 N respectively, the vertical components of the tensions are calculated as T1: 21.21 N and T2: 21.35 N. The net force acting on the mass includes the gravitational force and the two tension forces. The mass can be determined using the equation m = Fnet/a, resulting in a mass of approximately 5.017 kg. The discussion highlights the importance of balancing horizontal components of tension, which must be equal in magnitude. Understanding these forces is crucial for solving problems related to Newton's laws of motion.
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A mass is hanged by 2 cables, the first makes 30° with the ceiling while the second makes 60° with the ceiling. Find the attached mass if the first tension is 24.5 N and the second tension is 42.7 N.

my way:
T1=24.5N θ=30
T2=42.7N θ= -60
m=?
m=Fnet/a

the ans should be (m=5.017 Kg)
 
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How many forces act on the mass?
 
3 forces
Fg and 2 tension forces
 
Now find the vertical components of the two tensions.
 
T1: 24.5 sin 60=21.21N
T2: 42.7 sin 30=21.35N
 
shamma said:
T1: 24.5 sin 60=21.21N
T2: 42.7 sin 30=21.35N

If you draw a diagram you will notice that the above are the HORIZONTAL components.

(Incidentally, the horizontal components must be equal in magnitude)
 
yes, your right.
 
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