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Newtons 2nd law

  • Thread starter klr872
  • Start date
  • #1
2
0
A 29.8kg crate is at rest on a level floor, and the coefficient of kinetic friction is 0.338. The acceleration of gravity is 9.8 m/s. if the crate is pushed horizontally with a force of 188.535 N, how far does it move in 5.88 seconds?

i really need help with this...thanks!
 

Answers and Replies

  • #2
688
0
So use Newton2 law's formulae: F=ma; s=(at^2)/2
 
  • #3
2
0
so i did 188.535= (29.8) (A)
A= 6.33

D=(6.33)(5.88)^2 /2
=109.43

but thats not the right answer i dont know what im doing wrong
 
  • #4
rock.freak667
Homework Helper
6,230
31
The weight of the box is 29.8*9.81= (*)N
therefore the normal reaction,R= (*) N

the frictional force=uR where u=coefficient of friction.

find the resultant force and then equate that to ma
 

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