Newtons Laws, Finding tension in the tow cable and foce

AI Thread Summary
The discussion focuses on solving tension problems related to a rocket towing a container, emphasizing the need for a clear free body diagram. The rocket accelerates at 4.50 m/s², with a mass of 3.00 × 10³ kg, while the container has a mass of 1.00 × 10³ kg. The calculated force exerted by the rocket's engines is 1.80 × 10⁴ N, and the tension in the tow cable is determined to be 4.50 × 10³ N. Participants clarify the concept of normal force, noting it is not applicable in this scenario since there is no contact force involved. Understanding these forces and their relationships simplifies the problem-solving process.
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Homework Statement


Just started tension problems and having some trouble figuring out how to approach the problem. Thanks for any help in advance.

Consider a rocket that is taking off and towing a large container of trash. The
rocket’s engines exert a force, F, that causes the rocket and container to accelerate at
4.50 m/s2. The rocket has a mass of 3.00 × 103 kg, and the container has a mass of
1.00 × 103 kg. Find the tension in the tow cable and the force, F.


Homework Equations





The Attempt at a Solution

 
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Start with free body diagram and show us what you get.
 
mass a of the rocket. FN upward is the F(RA), downward we have m(ag) and also m(bg)?
mass b of container. Upward would be F(t) and FN would be F(RB)? downward m(bg).

I have the most trouble the free body diagrams.

Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
 
mjm3 said:
Upward would be F(t) and FN would be F(RB)? downward m(bg).

What is FN? :confused:
mjm3 said:
Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
Seems good. :smile:
 
Sorry I was meaning to write it as the Normal Force, NF better?
 
mjm3 said:
Sorry I was meaning to write it as the Normal Force, NF better?
I was afraid so...there is no normal force here! Normal forces come in play when there is a body in contact with another. See: http://en.wikipedia.org/wiki/Normal_force
For normal force it is general practice to write Fn or just N.
 
Thanks for the help. Just clarifying Fn made this system much easier to understand.
 
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