Newton's Laws of Motion PROBLEM

AI Thread Summary
A gardener applies a force of 150 N at a 60-degree angle to push a 20 kg lawn mower. The normal force is calculated as Fn = mg + FaSinθ, resulting in 326 N. The friction force is determined by multiplying the coefficient of kinetic friction (0.20) by the normal force. The next step involves finding the parallel component of the applied force and subtracting the friction force to apply F = ma for acceleration. This approach effectively leads to the calculation of the mower's horizontal acceleration.
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[SOLVED] Newton's Laws of Motion PROBLEM!

A gardener pushes down along the handle of a lawn mower of 20 kg mass with a force of 150 N. The handle makes an angle of 60 degrees with the ground. Calculate the horizontal acceleration of the mower if the coefficient of kinetic friction between its wheels and the gound is 0.20.


Attempt:
I've gotten this equation so far but I'm confused on what to do next!

Fn = mg + FaSin\theta

= 20(9.8) + 150sin60

Fn = 326 N <---?
 
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Fn is, I presume, the component of force normal to the ground. You calculated that in order to be able to find the friction force didn't you? The friction force is the coefficient of kinetic friction (0.20) multiplied by Fn. You will also want to find the component of foce parallel to the ground. That, minus the friction force, you put into "F= ma"
 

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