Newton's laws question [grade 12]

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SUMMARY

The discussion focuses on a physics problem involving a child sliding down a smooth metal fire pole, where the child has a mass of 35.7 kg and the pole height is 3.10 m. The child experiences a constant downward acceleration over a time span of 2.00 seconds. The net force acting on the child can be calculated using Newton's second law (Fnet = ma), leading to the determination of both the downward acceleration and the upward frictional force exerted by the pole.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with kinematic equations
  • Knowledge of forces, including gravitational force and friction
  • Ability to perform basic calculations involving mass and acceleration
NEXT STEPS
  • Calculate the downward acceleration using the kinematic equation: \( a = \frac{2s}{t^2} \)
  • Determine the net force acting on the child using \( Fnet = ma \)
  • Calculate the gravitational force using \( Fg = mg \)
  • Find the upward frictional force by applying \( F_{friction} = Fg - Fnet \)
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High school physics students, educators teaching Newton's laws, and anyone preparing for grade 12 physics examinations.

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Homework Statement



A tree house has a vertical "fire pole" of smooth metal, designed for quick exits. A child of mass 35.7 kg slides down the pole with constant acceleration, starting from rest. The pole is 3.10m high. The journey to the ground takes 2.00s.

a) what is the magnitude of the downward acceleration of the child?
b) what is the magnitude of the upward force of friction exerted by the pole on the child?

Homework Equations



Fnet = ma

The Attempt at a Solution



This is what I got so far but I have no idea on how to solve this...any pointers?

Fg = 35.7 x 9.8 = 349.86N

Umm if its constant acceleration or velocity the Fnet is 0 right?
 
Physics news on Phys.org
Height of the pole is given. The time taken to slide on the pole is given. Using kinematic equation find the acceleration. Obviously it is not g, because it is not a free fall. It leads to find the frictional force.
 

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