Newton's second law and tension

AI Thread Summary
The discussion focuses on solving a physics problem involving Newton's second law and tension in a system of two crates being lifted by a helicopter. The initial calculations for the tensions in the cables were incorrect due to a misunderstanding of the forces acting on each crate. It was clarified that the first crate experiences tension from both cables, while the second crate only has the tension from the first crate acting on it. Participants emphasized the importance of correctly drawing free body diagrams for both crates to accurately calculate the tensions. The user expressed gratitude for the clarification and now understands how to approach the problem correctly.
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Newton's second law and tension!

Homework Statement



A helicopter is lifting two crates simultaneously. One crate with a mass of 139 kg is attached to the helicopter by cable A. The second crate with a mass of 88 kg is hanging below the first crate and attached to the first crate by cable B. As the helicopter accelerates upward at a rate of 1.2 m/s2, what is the tension in each of the two cables (in kN)?

Homework Equations



Fnet=ma

The Attempt at a Solution



I drew a free body diagram and for the first crate (139 kg) I had tension pointing upwards and gravity pointing downwards. So I did the following calculations:

-mg + Ta= ma
Ta= m (a + g)
= 139 (1.2 +9.8)
= 1529 N
= 1.529 kN


For the second crate (88 kg), I had tension of the second crate pointing upwards, tension of the first crate pointing downwards and gravity pointing downwards. So I did the following calculations:

-mg- 1529 + Tb= ma
Tb= ma + mg + 1529
= m (a+g) + 1529
= 88 (1.2 + 9.8) + 1529
= 2497 N
= 2.497 kN

Both answers were wrong so I'm not so sure what I'm supposed to be doing for this question. Any help will be appreciated!
 
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warrior2014 said:
I drew a free body diagram and for the first crate (139 kg) I had tension pointing upwards and gravity pointing downwards.

Are you sure that those are all of the forces acting on crate A? After all, it has a rope (that is in tension) attached to the bottom of it as well...
 


The first crate is the one with two tensions acting on it (Cable A and Cable B). The second crate is only attached to Cable B. Do the second crate first!
 


So the calculations I did for crate A should actually be for crate B? and the calculations I did for crate B should be for crate A?
 


warrior2014 said:
So the calculations I did for crate A should actually be for crate B? and the calculations I did for crate B should be for crate A?

Sort of. Your logic was swapped. But don't just reverse the numbers. They will change when you redo it.
 


If I'm not only supposed to reverse the numbers then how exactly am I supposed to solve this problem??
 


warrior2014 said:
If I'm not only supposed to reverse the numbers then how exactly am I supposed to solve this problem??

Exactly as you were intending to solve it. Draw a free body diagram for crate B. Solve for the forces on it. Draw a free body diagram for crate A. Do the same.

What, specifically, is the source of your confusion?
 


I understand how to go about doing the question now. thank you for all of your help :)
 
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