Newton's second law to find mass

AI Thread Summary
The discussion revolves around calculating the mass of a helicopter using Newton's second law, given that it propels 2500 kg of air downward at 15 m/s and accelerates upward at 12.5 m/s². The initial calculation mistakenly concluded the helicopter's mass as 3750 kg, while the correct answer is 1680 kg, as indicated in the manual. Participants emphasize the importance of considering both the weight of the helicopter and the additional force required for upward acceleration. A free body diagram is suggested to clarify the forces acting on the helicopter. Ultimately, the misunderstanding is resolved through collaborative explanation and diagramming.
songoku
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Homework Statement


the rotor blades of a helicopter propel 2500 kg of air vertically downwards every second. The air, initially at rest, is accelerated to a speed of 15 ms-1. If the helicopter starts to rise with an acceleration of 12.5 ms-2, the mass of the helicopter is...

a. 1680 kg
b. 2500 kg
c. 2000 kg
d. 3000 kg
e. 3750 kg


Homework Equations


F = dp/dt


The Attempt at a Solution


let m1 = mass of helicopter and m2 = mass of air
When the helicopter reaches 15 ms-1 :

F = dp / dt

m1g = d(m2v) / dt

m1g = v dm2/dt

m1 = 15 * 2500 / 10 = 3750 kg

But in the manual, the answer is (a). Where is my mistake? Thanks
 
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songoku said:

Homework Statement


the rotor blades of a helicopter propel 2500 kg of air vertically downwards every second. The air, initially at rest, is accelerated to a speed of 15 ms-1. If the helicopter starts to rise with an acceleration of 12.5 ms-2, the mass of the helicopter is...

a. 1680 kg
b. 2500 kg
c. 2000 kg
d. 3000 kg
e. 3750 kg


Homework Equations


F = dp/dt


The Attempt at a Solution


let m1 = mass of helicopter and m2 = mass of air
When the helicopter reaches 15 ms-1 :

F = dp / dt

m1g = d(m2v) / dt

m1g = v dm2/dt

m1 = 15 * 2500 / 10 = 3750 kg

But in the manual, the answer is (a). Where is my mistake? Thanks
What if the helicopter simply hovered? What downward force would that require? Now add to that the upward acceleration. How much force does that require? Add them together.

AM
 
Hi AM

I don't really get what you mean...If the helicopter simply hovers, then the force required will the same as its weight, which like what I've done above. And there will be no acceleration if the helicopter hovers.

Thanks
 
songoku said:
Hi AM

I don't really get what you mean...If the helicopter simply hovers, then the force required will the same as its weight, which like what I've done above. And there will be no acceleration if the helicopter hovers.

Thanks
Do a free body diagram. The net force = mass x acceleration. What are the forces that act on the helicopter? Add them vectorally and set that net force to equal the mass x acceleration.

AM
 
Hi AM

Oh now I understand where my mistake was. Thanks a lot for your help ! :smile:
 
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