Nichrome Wire Brightness in Series: A Conductivity Homework Problem

AI Thread Summary
In a series circuit with two nichrome wires, P and Q, the brightness is influenced by their respective resistances, which depend on their diameters. Wire P, having a larger diameter, has a lower resistance compared to wire Q. Consequently, wire P will dissipate more power and reach a higher temperature, resulting in a brighter glow. The discussion emphasizes that brightness is directly related to the power dissipated in the wire, which is determined by its resistance and the current flowing through it. Understanding these principles is essential for solving the conductivity problem effectively.
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Homework Statement



There are 2 nichrome wires P and Q are connected in series to battery of emf , V .
Both P and Q are of same length bu the diameter of wire P is bigger than that of wire Q . When wire P and Q glow steadily , which one would glow brighter ?

Homework Equations





The Attempt at a Solution



What determines the brightness of the nichome wire ? Is it the temperature(as in when its hotter it glows more) ? Then how is different when the nichrome wires are connected in parallel ?
 
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Yes, the brightness will be determined by the temperature. The temperature will be determined by the power dissipated in the wire when a steady state has been reached.
You need an equation that relates the power in the wire to its resistance, and an equation that relates the resistance of the wire to its cross section.
 


Stonebridge said:
Yes, the brightness will be determined by the temperature. The temperature will be determined by the power dissipated in the wire when a steady state has been reached.
You need an equation that relates the power in the wire to its resistance, and an equation that relates the resistance of the wire to its cross section.

thanks !
 

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