(no friction) inclined plane acceleration

isuru.imsd
Messages
1
Reaction score
0

Homework Statement





Homework Equations


on a inclined plane an object is at stationery. β accelaration is applied horizontally towards the inclined plane(no friction at all no where) being object is at rest relative to the inclined plane.the angle of the inclined plane is θ sinθ=1/x.what is the accelaration(β). I am a srilankan my physics test sum today
Code:
http://imageshack.us/photo/my-images/542/snapshot20111201.jpg/



The Attempt at a Solution

 
Physics news on Phys.org
If you apply an acceleration \beta against an incline plane then you are applying a force m \beta against that plane and the plane pushes back with a normal force with equal strength but with a different direction. Calculate the force pushing your object up and set this equal to the force of gravity pulling it down mg and you're done.
Alternatively parameterize gravity and the pushing force into new components parallel to the ramp and solve for these being equal.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top