No Idea how to work this out - Charging and discharging an iPod

Click For Summary

Discussion Overview

The discussion revolves around a homework problem related to the charging and discharging characteristics of an iPod Nano. Participants are tasked with calculating the power consumption of the device's screen and audio output separately, as well as determining the power depletion timeline when the screen is intermittently activated.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant notes that it takes about 5 hours for the iPod to run out of power with the screen on and all other functions off, and 24 hours when only the audio function is used.
  • Another participant questions how much power is used to charge the iPod and how much energy is stored during the charging time.
  • There is a calculation presented for the energy used in charging, where one participant calculates the energy as 5400 joules based on the charging time of 90 minutes.
  • Participants discuss the formulas for power (P = I . V) and energy (E = P . t), with one participant calculating the power as 2.5 watts based on the charging specifications.
  • Another participant attempts to calculate the total energy stored during charging, arriving at 45000 joules, and questions how to find the discharge power based on the energy and discharge time.
  • There is a follow-up calculation regarding the discharge power, suggesting it may be calculated as 45000J divided by 86400 seconds (24 hours).

Areas of Agreement / Disagreement

Participants are working collaboratively on the problem, but there is no consensus on the final calculations or methods to approach the problem. Uncertainty remains regarding the correct application of formulas and the interpretation of the results.

Contextual Notes

Participants express uncertainty about the next steps in their calculations and the application of formulas. There are unresolved mathematical steps and assumptions about the energy consumption of the iPod's functions.

andyb1990
Messages
33
Reaction score
0
No Idea how to work this out! -- Charging and discharging an iPod

Homework Statement



It takes about 5 hours for a fully charged ipod nano to run out of power when its screen is left on and all other functions are switched off. Subsequently, it takes about 90 minutes to recharge the ipod from a charging unit with a 5V and 500mA output. The same ipod takes about 24hours to run out of power when only the audio function is used

a) calculate the power consumption of the screen and audio output separately

b) calculate when the power will run out if the user switches on the screen for 10 seconds every 3mins (i.e. about once every track) assuming the ipod is fully charged at the start.

Homework Equations





The Attempt at a Solution



I don't know where to start with this question been stuck on it for hours and can't get anything from it :( please help!
 
Physics news on Phys.org


andyb1990 said:

Homework Statement



It takes about 5 hours for a fully charged ipod nano to run out of power when its screen is left on and all other functions are switched off. Subsequently, it takes about 90 minutes to recharge the ipod from a charging unit with a 5V and 500mA output. The same ipod takes about 24hours to run out of power when only the audio function is used

a) calculate the power consumption of the screen and audio output separately

b) calculate when the power will run out if the user switches on the screen for 10 seconds every 3mins (i.e. about once every track) assuming the ipod is fully charged at the start.

Homework Equations





The Attempt at a Solution



I don't know where to start with this question been stuck on it for hours and can't get anything from it :( please help!

You are given complete information about the charging situation. How much power is used to charge the iPod? How much energy is stored in the battery during the charging time?
 


is the power of the iPod

90*60 = 5400joules?
 


andyb1990 said:
is the power of the iPod

90*60 = 5400joules?

What is that? 90 minutes * 60 seconds/minute ?

What is the equation for power P in terms of voltage V and current I ?

What is the equation for Energy E in terms of power P and time t ?
 


so the formula for power

P= I . V ?? ----> 5 x 0.5 = 2.5 watts?

E= P . t -----> 2.5 x (5*60*60) = 45000 ?

then I'm unsure on what to do?
 


andyb1990 said:
so the formula for power

P= I . V ?? ----> 5 x 0.5 = 2.5 watts?

E= P . t -----> 2.5 x (5*60*60) = 45000 ?

then I'm unsure on what to do?

Good! Be sure to carry units along in your equations, so your E = 45000J.

So what is the discharge power if it takes 24 hours to discharge that energy?
 


would it be

45000J/ 24*60*60??
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 52 ·
2
Replies
52
Views
4K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K