No, that is not correct. The correct answer is F_t(y) = [m(gL - gy)]/L.

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The discussion centers on calculating the tension in a uniform rope of length L and mass m, hung vertically. The incorrect formula presented was F_t(y) = [m(L-y)*g], which was challenged due to unit discrepancies. The correct formula is F_t(y) = [m(gL - gy)]/L, which accurately reflects the tension at a distance y from the bottom of the rope. The conversation highlights the importance of ensuring consistent units and understanding the physical implications of the formulas used. Ultimately, the correct expression for tension incorporates both mass distribution and gravitational effects.
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a uniform rope of length L and mass m is hung vertically. what is the tension a distance y from the bottom?

my final anwer that i got was F_t(y)= [m(L-y)*g]

is this correct?
 
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No.

For one thing, the units are different on the left side of the equation vs. the right side.

How did you get your answer?

What does the answer you posted say in the case that y = L ?
 
force of tension a distance y from the bottom = m [(L-y)/L]*g
tension = mgh

mass per unit length times gravity
 
ahhgidaa said:
force of tension a distance y from the bottom = m [(L-y)/L]*g
tension = mgh

mass per unit length times gravity

yup! :smile:
 
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